-z2+14z-49=0

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Solution for -z2+14z-49=0 equation: 



-z2+14z-49=0

We add all the numbers together, and all the variables

-1z^2+14z-49=0

a = -1; b = 14; c = -49;
Δ = b2-4ac
Δ = 142-4·(-1)·(-49)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$z=\frac{-b}{2a}=\frac{-14}{-2}=+7$

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