.(-7s+4)-(-8s+4)=

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Solution for .(-7s+4)-(-8s+4)= equation:



.(-7s+4)-(-8s+4)=
We move all terms to the left:
.(-7s+4)-(-8s+4)-()=0
We add all the numbers together, and all the variables
.(-7s+4)-(-8s+4)=0
We multiply parentheses
-7s^2-(-8s+4)+=0
We get rid of parentheses
-7s^2+8s-4+=0
We add all the numbers together, and all the variables
-7s^2+8s=0
a = -7; b = 8; c = 0;
Δ = b2-4ac
Δ = 82-4·(-7)·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8}{2*-7}=\frac{-16}{-14} =1+1/7 $
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8}{2*-7}=\frac{0}{-14} =0 $

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