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.(b+12)2=81

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Solution for .(b+12)2=81 equation:



.(b+12)2=81
We move all terms to the left:
.(b+12)2-(81)=0
We multiply parentheses
b^2-81+=0
We add all the numbers together, and all the variables
b^2=0
a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
b=\frac{-b}{2a}=\frac{0}{2}=0

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