.-1-n=2n-2(1+2n)

Solution for .-1-n=2n-2(1+2n) equation:

.-1-n=2n-2(1+2n)

We move all terms to the left:

.-1-n-(2n-2(1+2n))=0

We add all the numbers together, and all the variables

-n-(2n-2(2n+1))-1+.=0

We add all the numbers together, and all the variables

-1n-(2n-2(2n+1))=0


We calculate terms in parentheses: -(2n-2(2n+1)), so:

2n-2(2n+1)

We multiply parentheses

2n-4n-2

We add all the numbers together, and all the variables

-2n-2

Back to the equation:

-(-2n-2)


We get rid of parentheses

-1n+2n+2=0

We add all the numbers together, and all the variables

n+2=0

We move all terms containing n to the left, all other terms to the right

n=-2