.-11+3(b+5)=7

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Solution for .-11+3(b+5)=7 equation: 



.-11+3(b+5)=7

We move all terms to the left:

.-11+3(b+5)-(7)=0

determiningTheFunctionDomain
3(b+5)-11-7+.=0

We add all the numbers together, and all the variables

3(b+5)=0

We multiply parentheses

3b+15=0

We move all terms containing b to the left, all other terms to the right

3b=-15

b=-15/3

b=-5

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