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.00101=x2+.1x
We move all terms to the left:
.00101-(x2+.1x)=0
We add all the numbers together, and all the variables
-(+x^2+.1x)+.00101=0
We add all the numbers together, and all the variables
-(+x^2+.1x)+0.00101=0
We get rid of parentheses
-x^2-.1x+0.00101=0
We add all the numbers together, and all the variables
-1x^2-0.1x+0.00101=0
a = -1; b = -0.1; c = +0.00101;
Δ = b2-4ac
Δ = -0.12-4·(-1)·0.00101
Δ = 0.01404
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.1)-\sqrt{0.01404}}{2*-1}=\frac{0.1-\sqrt{0.01404}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.1)+\sqrt{0.01404}}{2*-1}=\frac{0.1+\sqrt{0.01404}}{-2} $
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