.01x+.001=1/100(x=10)

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Solution for .01x+.001=1/100(x=10) equation: 



.01x+.001=1/100(x=10)

We move all terms to the left:

.01x+.001-(1/100(x)=0



Domain of the equation: 100x+.001!=0

We move all terms containing x to the left, all other terms to the right

100x!=-.001

x!=-.001/100

x!=-.001/100

x∈R



We multiply all the terms by the denominator


(.01x)*100x+.001-(1=0

We add all the numbers together, and all the variables

(+.01x)*100x+.001-(1=0

We add all the numbers together, and all the variables

(+.01x)*100x=0

We multiply parentheses

100x^2=0

a = 100; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·100·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{200}=0$

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