.02(2t+8)=.04(t+1)+.12

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Solution for .02(2t+8)=.04(t+1)+.12 equation: 


Simplifying
0.02(2t + 8) = 0.04(t + 1) + 0.12

Reorder the terms:
0.02(8 + 2t) = 0.04(t + 1) + 0.12
(8 * 0.02 + 2t * 0.02) = 0.04(t + 1) + 0.12
(0.16 + 0.04t) = 0.04(t + 1) + 0.12

Reorder the terms:
0.16 + 0.04t = 0.04(1 + t) + 0.12
0.16 + 0.04t = (1 * 0.04 + t * 0.04) + 0.12
0.16 + 0.04t = (0.04 + 0.04t) + 0.12

Reorder the terms:
0.16 + 0.04t = 0.04 + 0.12 + 0.04t

Combine like terms: 0.04 + 0.12 = 0.16
0.16 + 0.04t = 0.16 + 0.04t

Add '-0.16' to each side of the equation.
0.16 + -0.16 + 0.04t = 0.16 + -0.16 + 0.04t

Combine like terms: 0.16 + -0.16 = 0.00
0.00 + 0.04t = 0.16 + -0.16 + 0.04t
0.04t = 0.16 + -0.16 + 0.04t

Combine like terms: 0.16 + -0.16 = 0.00
0.04t = 0.00 + 0.04t
0.04t = 0.04t

Add '-0.04t' to each side of the equation.
0.04t + -0.04t = 0.04t + -0.04t

Combine like terms: 0.04t + -0.04t = 0.00
0.00 = 0.04t + -0.04t

Combine like terms: 0.04t + -0.04t = 0.00
0.00 = 0.00

Solving
0.00 = 0.00

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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