.02(4t-1)=.08(t-3)+.22

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Solution for .02(4t-1)=.08(t-3)+.22 equation:


Simplifying
0.02(4t + -1) = 0.08(t + -3) + 0.22

Reorder the terms:
0.02(-1 + 4t) = 0.08(t + -3) + 0.22
(-1 * 0.02 + 4t * 0.02) = 0.08(t + -3) + 0.22
(-0.02 + 0.08t) = 0.08(t + -3) + 0.22

Reorder the terms:
-0.02 + 0.08t = 0.08(-3 + t) + 0.22
-0.02 + 0.08t = (-3 * 0.08 + t * 0.08) + 0.22
-0.02 + 0.08t = (-0.24 + 0.08t) + 0.22

Reorder the terms:
-0.02 + 0.08t = -0.24 + 0.22 + 0.08t

Combine like terms: -0.24 + 0.22 = -0.02
-0.02 + 0.08t = -0.02 + 0.08t

Add '0.02' to each side of the equation.
-0.02 + 0.02 + 0.08t = -0.02 + 0.02 + 0.08t

Combine like terms: -0.02 + 0.02 = 0.00
0.00 + 0.08t = -0.02 + 0.02 + 0.08t
0.08t = -0.02 + 0.02 + 0.08t

Combine like terms: -0.02 + 0.02 = 0.00
0.08t = 0.00 + 0.08t
0.08t = 0.08t

Add '-0.08t' to each side of the equation.
0.08t + -0.08t = 0.08t + -0.08t

Combine like terms: 0.08t + -0.08t = 0.00
0.00 = 0.08t + -0.08t

Combine like terms: 0.08t + -0.08t = 0.00
0.00 = 0.00

Solving
0.00 = 0.00

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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