.02(6t+7)=.12(t+1)+.02

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Solution for .02(6t+7)=.12(t+1)+.02 equation:


Simplifying
0.02(6t + 7) = 0.12(t + 1) + 0.02

Reorder the terms:
0.02(7 + 6t) = 0.12(t + 1) + 0.02
(7 * 0.02 + 6t * 0.02) = 0.12(t + 1) + 0.02
(0.14 + 0.12t) = 0.12(t + 1) + 0.02

Reorder the terms:
0.14 + 0.12t = 0.12(1 + t) + 0.02
0.14 + 0.12t = (1 * 0.12 + t * 0.12) + 0.02
0.14 + 0.12t = (0.12 + 0.12t) + 0.02

Reorder the terms:
0.14 + 0.12t = 0.12 + 0.02 + 0.12t

Combine like terms: 0.12 + 0.02 = 0.14
0.14 + 0.12t = 0.14 + 0.12t

Add '-0.14' to each side of the equation.
0.14 + -0.14 + 0.12t = 0.14 + -0.14 + 0.12t

Combine like terms: 0.14 + -0.14 = 0.00
0.00 + 0.12t = 0.14 + -0.14 + 0.12t
0.12t = 0.14 + -0.14 + 0.12t

Combine like terms: 0.14 + -0.14 = 0.00
0.12t = 0.00 + 0.12t
0.12t = 0.12t

Add '-0.12t' to each side of the equation.
0.12t + -0.12t = 0.12t + -0.12t

Combine like terms: 0.12t + -0.12t = 0.00
0.00 = 0.12t + -0.12t

Combine like terms: 0.12t + -0.12t = 0.00
0.00 = 0.00

Solving
0.00 = 0.00

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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