.03(4t+5)=.12(t+3)-.21

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Solution for .03(4t+5)=.12(t+3)-.21 equation: 


Simplifying
0.03(4t + 5) = 0.12(t + 3) + -0.21

Reorder the terms:
0.03(5 + 4t) = 0.12(t + 3) + -0.21
(5 * 0.03 + 4t * 0.03) = 0.12(t + 3) + -0.21
(0.15 + 0.12t) = 0.12(t + 3) + -0.21

Reorder the terms:
0.15 + 0.12t = 0.12(3 + t) + -0.21
0.15 + 0.12t = (3 * 0.12 + t * 0.12) + -0.21
0.15 + 0.12t = (0.36 + 0.12t) + -0.21

Reorder the terms:
0.15 + 0.12t = 0.36 + -0.21 + 0.12t

Combine like terms: 0.36 + -0.21 = 0.15
0.15 + 0.12t = 0.15 + 0.12t

Add '-0.15' to each side of the equation.
0.15 + -0.15 + 0.12t = 0.15 + -0.15 + 0.12t

Combine like terms: 0.15 + -0.15 = 0.00
0.00 + 0.12t = 0.15 + -0.15 + 0.12t
0.12t = 0.15 + -0.15 + 0.12t

Combine like terms: 0.15 + -0.15 = 0.00
0.12t = 0.00 + 0.12t
0.12t = 0.12t

Add '-0.12t' to each side of the equation.
0.12t + -0.12t = 0.12t + -0.12t

Combine like terms: 0.12t + -0.12t = 0.00
0.00 = 0.12t + -0.12t

Combine like terms: 0.12t + -0.12t = 0.00
0.00 = 0.00

Solving
0.00 = 0.00

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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