.03x+.01(2,600-x)=100,000

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Solution for .03x+.01(2,600-x)=100,000 equation:



.03x+.01(2.600-x)=100.000
We move all terms to the left:
.03x+.01(2.600-x)-(100.000)=0
We add all the numbers together, and all the variables
.03x+.01(-1x+2.6)-100=0
We multiply parentheses
.03x-0.01x+0.026-100=0
We add all the numbers together, and all the variables
0.02x-99.974=0
We move all terms containing x to the left, all other terms to the right
0.02x=99.974
x=99.974/0.02
x=4998+0.013999999999996/0.02

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