.03x+.01(2,600-x)=100,000

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Solution for .03x+.01(2,600-x)=100,000 equation: 



.03x+.01(2.600-x)=100.000

We move all terms to the left:

.03x+.01(2.600-x)-(100.000)=0

We add all the numbers together, and all the variables

.03x+.01(-1x+2.6)-100=0

We multiply parentheses

.03x-0.01x+0.026-100=0

We add all the numbers together, and all the variables

0.02x-99.974=0

We move all terms containing x to the left, all other terms to the right

0.02x=99.974

x=99.974/0.02

x=4998+0.013999999999996/0.02

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