.03x+.04(1200-x)=440

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Solution for .03x+.04(1200-x)=440 equation: 



.03x+.04(1200-x)=440

We move all terms to the left:

.03x+.04(1200-x)-(440)=0

We add all the numbers together, and all the variables

.03x+.04(-1x+1200)-440=0

We multiply parentheses

.03x-0.04x+48-440=0

We add all the numbers together, and all the variables

-0.01x-392=0

We move all terms containing x to the left, all other terms to the right

-0.01x=392

x=392/-0.01

x=-39200

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