.05(4t-2)=.20(t+3)-.70

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Solution for .05(4t-2)=.20(t+3)-.70 equation: 


Simplifying
0.05(4t + -2) = 0.20(t + 3) + -0.70

Reorder the terms:
0.05(-2 + 4t) = 0.20(t + 3) + -0.70
(-2 * 0.05 + 4t * 0.05) = 0.20(t + 3) + -0.70
(-0.1 + 0.2t) = 0.20(t + 3) + -0.70

Reorder the terms:
-0.1 + 0.2t = 0.20(3 + t) + -0.70
-0.1 + 0.2t = (3 * 0.20 + t * 0.20) + -0.70
-0.1 + 0.2t = (0.6 + 0.20t) + -0.70

Reorder the terms:
-0.1 + 0.2t = 0.6 + -0.70 + 0.20t

Combine like terms: 0.6 + -0.70 = -0.1
-0.1 + 0.2t = -0.1 + 0.20t

Add '0.1' to each side of the equation.
-0.1 + 0.1 + 0.2t = -0.1 + 0.1 + 0.20t

Combine like terms: -0.1 + 0.1 = 0.0
0.0 + 0.2t = -0.1 + 0.1 + 0.20t
0.2t = -0.1 + 0.1 + 0.20t

Combine like terms: -0.1 + 0.1 = 0.0
0.2t = 0.0 + 0.20t
0.2t = 0.20t

Add '-0.2t' to each side of the equation.
0.2t + -0.2t = 0.20t + -0.2t

Combine like terms: 0.2t + -0.2t = 0.0
0.0 = 0.20t + -0.2t

Combine like terms: 0.20t + -0.2t = 0.00
0.0 = 0.00

Solving
0.0 = 0.00

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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