.06-0.01(x+1)=-0.02(2-x)

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Solution for .06-0.01(x+1)=-0.02(2-x) equation: 



.06-0.01(x+1)=-0.02(2-x)

We move all terms to the left:

.06-0.01(x+1)-(-0.02(2-x))=0

We add all the numbers together, and all the variables

-0.01(x+1)-(-0.02(-1x+2))+.06=0

We add all the numbers together, and all the variables

-0.01(x+1)-(-0.02(-1x+2))+0.06=0

We multiply parentheses

-0.01x-(-0.02(-1x+2))-0.01+0.06=0



We calculate terms in parentheses: -(-0.02(-1x+2)), so:

-0.02(-1x+2)

We multiply parentheses

0.02x-0.04

Back to the equation:

-(0.02x-0.04)



We add all the numbers together, and all the variables

-0.01x-(0.02x-0.04)+0.05=0

We get rid of parentheses

-0.01x-0.02x+0.04+0.05=0

We add all the numbers together, and all the variables

-0.03x+0.09=0

We move all terms containing x to the left, all other terms to the right

-0.03x=-0.09

x=-0.09/-0.03

x=+3

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