.1(y-2)+.03(y-4)=.02(10)

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Solution for .1(y-2)+.03(y-4)=.02(10) equation:


Simplifying
0.1(y + -2) + 0.03(y + -4) = 0.02(10)

Reorder the terms:
0.1(-2 + y) + 0.03(y + -4) = 0.02(10)
(-2 * 0.1 + y * 0.1) + 0.03(y + -4) = 0.02(10)
(-0.2 + 0.1y) + 0.03(y + -4) = 0.02(10)

Reorder the terms:
-0.2 + 0.1y + 0.03(-4 + y) = 0.02(10)
-0.2 + 0.1y + (-4 * 0.03 + y * 0.03) = 0.02(10)
-0.2 + 0.1y + (-0.12 + 0.03y) = 0.02(10)

Reorder the terms:
-0.2 + -0.12 + 0.1y + 0.03y = 0.02(10)

Combine like terms: -0.2 + -0.12 = -0.32
-0.32 + 0.1y + 0.03y = 0.02(10)

Combine like terms: 0.1y + 0.03y = 0.13y
-0.32 + 0.13y = 0.02(10)

Multiply 0.02 * 10
-0.32 + 0.13y = 0.2

Solving
-0.32 + 0.13y = 0.2

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '0.32' to each side of the equation.
-0.32 + 0.32 + 0.13y = 0.2 + 0.32

Combine like terms: -0.32 + 0.32 = 0.00
0.00 + 0.13y = 0.2 + 0.32
0.13y = 0.2 + 0.32

Combine like terms: 0.2 + 0.32 = 0.52
0.13y = 0.52

Divide each side by '0.13'.
y = 4

Simplifying
y = 4

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