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.10x+.25x(x+6)=6.05
We move all terms to the left:
.10x+.25x(x+6)-(6.05)=0
We add all the numbers together, and all the variables
.10x+.25x(x+6)-6.05=0
We multiply parentheses
x^2+.10x+6x-6.05=0
We add all the numbers together, and all the variables
x^2+6.1x-6.05=0
a = 1; b = 6.1; c = -6.05;
Δ = b2-4ac
Δ = 6.12-4·1·(-6.05)
Δ = 61.41
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6.1)-\sqrt{61.41}}{2*1}=\frac{-6.1-\sqrt{61.41}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6.1)+\sqrt{61.41}}{2*1}=\frac{-6.1+\sqrt{61.41}}{2} $
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