.11x+0.2x(x-2)=0.01(5x-5)

Solution for .11x+0.2x(x-2)=0.01(5x-5) equation:

.11x+0.2x(x-2)=0.01(5x-5)

We move all terms to the left:

.11x+0.2x(x-2)-(0.01(5x-5))=0

We multiply parentheses

0x^2+.11x+0x-(0.01(5x-5))=0


We calculate terms in parentheses: -(0.01(5x-5)), so:

0.01(5x-5)

We multiply parentheses

0.05x-0.05

Back to the equation:

-(0.05x-0.05)


We add all the numbers together, and all the variables

x^2+1.11x-(0.05x-0.05)=0

We get rid of parentheses

x^2+1.11x-0.05x+0.05=0

We add all the numbers together, and all the variables

x^2+1.06x+0.05=0

a = 1; b = 1.06; c = +0.05;
Δ = b2-4ac
Δ = 1.062-4·1·0.05
Δ = 0.9236
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.06)-\sqrt{0.9236}}{2*1}=\frac{-1.06-\sqrt{0.9236}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.06)+\sqrt{0.9236}}{2*1}=\frac{-1.06+\sqrt{0.9236}}{2}
$