.120=x(0.043x)

Solution for .120=x(0.043x) equation:

.120=x(0.043x)

We move all terms to the left:

.120-(x(0.043x))=0

We add all the numbers together, and all the variables

-(x(+0.043x))+.120=0

We add all the numbers together, and all the variables

-(x(+0.043x))+0.12=0


We calculate terms in parentheses: -(x(+0.043x)), so:

x(+0.043x)

We multiply parentheses

0x^2

We add all the numbers together, and all the variables

x^2

Back to the equation:

-(x^2)


We add all the numbers together, and all the variables

-1x^2+0.12=0

a = -1; b = 0; c = +0.12;
Δ = b2-4ac
Δ = 02-4·(-1)·0.12
Δ = 0.48
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{0.48}}{2*-1}=\frac{0-\sqrt{0.48}}{-2}
=-\frac{\sqrt{}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{0.48}}{2*-1}=\frac{0+\sqrt{0.48}}{-2}
=\frac{\sqrt{}}{-2}
$