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.19y+.07y(y+5000)=1910
We move all terms to the left:
.19y+.07y(y+5000)-(1910)=0
We multiply parentheses
y^2+.19y+5000y-1910=0
We add all the numbers together, and all the variables
y^2+5000.19y-1910=0
a = 1; b = 5000.19; c = -1910;
Δ = b2-4ac
Δ = 5000.192-4·1·(-1910)
Δ = 25009540.0361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5000.19)-\sqrt{25009540.0361}}{2*1}=\frac{-5000.19-\sqrt{25009540.0361}}{2} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5000.19)+\sqrt{25009540.0361}}{2*1}=\frac{-5000.19+\sqrt{25009540.0361}}{2} $
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