.1x-.05x(x-20)=12

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Solution for .1x-.05x(x-20)=12 equation:


Simplifying
0.1x + -0.05x(x + -20) = 12

Reorder the terms:
0.1x + -0.05x(-20 + x) = 12
0.1x + (-20 * -0.05x + x * -0.05x) = 12
0.1x + (1x + -0.05x2) = 12

Combine like terms: 0.1x + 1x = 1.1x
1.1x + -0.05x2 = 12

Solving
1.1x + -0.05x2 = 12

Solving for variable 'x'.

Reorder the terms:
-12 + 1.1x + -0.05x2 = 12 + -12

Combine like terms: 12 + -12 = 0
-12 + 1.1x + -0.05x2 = 0

Begin completing the square.  Divide all terms by
-0.05 the coefficient of the squared term: 

Divide each side by '-0.05'.
240 + -22x + x2 = 0

Move the constant term to the right:

Add '-240' to each side of the equation.
240 + -22x + -240 + x2 = 0 + -240

Reorder the terms:
240 + -240 + -22x + x2 = 0 + -240

Combine like terms: 240 + -240 = 0
0 + -22x + x2 = 0 + -240
-22x + x2 = 0 + -240

Combine like terms: 0 + -240 = -240
-22x + x2 = -240

The x term is -22x.  Take half its coefficient (-11).
Square it (121) and add it to both sides.

Add '121' to each side of the equation.
-22x + 121 + x2 = -240 + 121

Reorder the terms:
121 + -22x + x2 = -240 + 121

Combine like terms: -240 + 121 = -119
121 + -22x + x2 = -119

Factor a perfect square on the left side:
(x + -11)(x + -11) = -119

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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