.2(1-x)=2(4+.1x)

Solution for .2(1-x)=2(4+.1x) equation:

.2(1-x)=2(4+.1x)

We move all terms to the left:

.2(1-x)-(2(4+.1x))=0

We add all the numbers together, and all the variables

.2(-1x+1)-(2(.1x+4))=0

We multiply parentheses

-0.2x-(2(.1x+4))+0.2=0


We calculate terms in parentheses: -(2(.1x+4)), so:

2(.1x+4)

We multiply parentheses

2x+8

Back to the equation:

-(2x+8)


We get rid of parentheses

-0.2x-2x-8+0.2=0

We add all the numbers together, and all the variables

-2.2x-7.8=0

We move all terms containing x to the left, all other terms to the right

-2.2x=7.8

x=7.8/-2.2

x=-3+1/1.83333333333