.2(10b+60)=-4(b-12)

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Solution for .2(10b+60)=-4(b-12) equation: 



.2(10b+60)=-4(b-12)

We move all terms to the left:

.2(10b+60)-(-4(b-12))=0

We multiply parentheses

2b-(-4(b-12))+12=0



We calculate terms in parentheses: -(-4(b-12)), so:

-4(b-12)

We multiply parentheses

-4b+48

Back to the equation:

-(-4b+48)



We get rid of parentheses

2b+4b-48+12=0

We add all the numbers together, and all the variables

6b-36=0

We move all terms containing b to the left, all other terms to the right

6b=36

b=36/6

b=6

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