.2(15z-5)=4(16z+4)

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Solution for .2(15z-5)=4(16z+4) equation: 



.2(15z-5)=4(16z+4)

We move all terms to the left:

.2(15z-5)-(4(16z+4))=0

We multiply parentheses

3z-(4(16z+4))-1=0



We calculate terms in parentheses: -(4(16z+4)), so:

4(16z+4)

We multiply parentheses

64z+16

Back to the equation:

-(64z+16)



We get rid of parentheses

3z-64z-16-1=0

We add all the numbers together, and all the variables

-61z-17=0

We move all terms containing z to the left, all other terms to the right

-61z=17

z=17/-61

z=-17/61

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