.2(2k-1)=4(k-2)

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Solution for .2(2k-1)=4(k-2) equation: 



.2(2k-1)=4(k-2)

We move all terms to the left:

.2(2k-1)-(4(k-2))=0

We multiply parentheses

0.4k-(4(k-2))-0.2=0



We calculate terms in parentheses: -(4(k-2)), so:

4(k-2)

We multiply parentheses

4k-8

Back to the equation:

-(4k-8)



We get rid of parentheses

0.4k-4k+8-0.2=0

We add all the numbers together, and all the variables

-3.6k+7.8=0

We move all terms containing k to the left, all other terms to the right

-3.6k=-7.8

k=-7.8/-3.6

k=2+0.6/3.6

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