.2(4(k+2)-(3-k))=4

Solution for .2(4(k+2)-(3-k))=4 equation:

Simplifying
0.2(4(k + 2) + -1(3 + -1k)) = 4

Reorder the terms:
0.2(4(2 + k) + -1(3 + -1k)) = 4
0.2((2 * 4 + k * 4) + -1(3 + -1k)) = 4
0.2((8 + 4k) + -1(3 + -1k)) = 4
0.2(8 + 4k + (3 * -1 + -1k * -1)) = 4
0.2(8 + 4k + (-3 + 1k)) = 4

Reorder the terms:
0.2(8 + -3 + 4k + 1k) = 4

Combine like terms: 8 + -3 = 5
0.2(5 + 4k + 1k) = 4

Combine like terms: 4k + 1k = 5k
0.2(5 + 5k) = 4
(5 * 0.2 + 5k * 0.2) = 4
(1 + 1k) = 4

Solving
1 + 1k = 4

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 1k = 4 + -1

Combine like terms: 1 + -1 = 0
0 + 1k = 4 + -1
1k = 4 + -1

Combine like terms: 4 + -1 = 3
1k = 3

Divide each side by '1'.
k = 3

Simplifying
k = 3