.2(4x+20)+3x=6(x-3)

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Solution for .2(4x+20)+3x=6(x-3) equation: 



.2(4x+20)+3x=6(x-3)

We move all terms to the left:

.2(4x+20)+3x-(6(x-3))=0

We add all the numbers together, and all the variables

3x+.2(4x+20)-(6(x-3))=0

We multiply parentheses

3x+0.8x-(6(x-3))+4=0



We calculate terms in parentheses: -(6(x-3)), so:

6(x-3)

We multiply parentheses

6x-18

Back to the equation:

-(6x-18)



We add all the numbers together, and all the variables

3.8x-(6x-18)+4=0

We get rid of parentheses

3.8x-6x+18+4=0

We add all the numbers together, and all the variables

-2.2x+22=0

We move all terms containing x to the left, all other terms to the right

-2.2x=-22

x=-22/-2.2

x=+10

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