.2(b-4)-2(3b-6)=2(3b-8)

Solution for .2(b-4)-2(3b-6)=2(3b-8) equation:

.2(b-4)-2(3b-6)=2(3b-8)

We move all terms to the left:

.2(b-4)-2(3b-6)-(2(3b-8))=0

We multiply parentheses

0.2b-6b-(2(3b-8))-0.8+12=0


We calculate terms in parentheses: -(2(3b-8)), so:

2(3b-8)

We multiply parentheses

6b-16

Back to the equation:

-(6b-16)


We add all the numbers together, and all the variables

-5.8b-(6b-16)+11.2=0

We get rid of parentheses

-5.8b-6b+16+11.2=0

We add all the numbers together, and all the variables

-11.8b+27.2=0

We move all terms containing b to the left, all other terms to the right

-11.8b=-27.2

b=-27.2/-11.8

b=2+2.25/7.375