.20(y-9)+0.18y=0/12y-0.05(10)

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Solution for .20(y-9)+0.18y=0/12y-0.05(10) equation:



.20(y-9)+0.18y=0/12y-0.05(10)
We move all terms to the left:
.20(y-9)+0.18y-(0/12y-0.05(10))=0
Domain of the equation: 12y-0.0510)!=0
y∈R
We add all the numbers together, and all the variables
.20(y-9)+0.18y-(0/12y-0.051)=0
We add all the numbers together, and all the variables
0.18y+.20(y-9)-(0/12y-0.051)=0
We multiply parentheses
0.18y+0.2y-(0/12y-0.051)-1.8=0
We get rid of parentheses
0.18y+0.2y-0/12y+0.051-1.8=0
We multiply all the terms by the denominator
(0.18y)*12y+(0.2y)*12y+(0.051)*12y-(1.8)*12y-0=0
We add all the numbers together, and all the variables
(+0.18y)*12y+(+0.2y)*12y+(0.051)*12y-(1.8)*12y-0=0
We add all the numbers together, and all the variables
(+0.18y)*12y+(+0.2y)*12y+(0.051)*12y-(1.8)*12y=0
We multiply parentheses
0y^2+0y^2+0.612y-21.6y=0
We add all the numbers together, and all the variables
2y^2-20.988y=0
a = 2; b = -20.988; c = 0;
Δ = b2-4ac
Δ = -20.9882-4·2·0
Δ = 440.496144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20.988)-\sqrt{440.496144}}{2*2}=\frac{20.988-\sqrt{440.496144}}{4} $
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20.988)+\sqrt{440.496144}}{2*2}=\frac{20.988+\sqrt{440.496144}}{4} $

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