.25(40-8x)=19x+2-5

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Solution for .25(40-8x)=19x+2-5 equation: 



.25(40-8x)=19x+2-5

We move all terms to the left:

.25(40-8x)-(19x+2-5)=0

We add all the numbers together, and all the variables

.25(-8x+40)-(19x-3)=0

We multiply parentheses

-2x-(19x-3)+10=0

We get rid of parentheses

-2x-19x+3+10=0

We add all the numbers together, and all the variables

-21x+13=0

We move all terms containing x to the left, all other terms to the right

-21x=-13

x=-13/-21

x=13/21

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