.3x+.10(100-x)=23

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Solution for .3x+.10(100-x)=23 equation: 



.3x+.10(100-x)=23

We move all terms to the left:

.3x+.10(100-x)-(23)=0

We add all the numbers together, and all the variables

.3x+.10(-1x+100)-23=0

We multiply parentheses

.3x-0.1x+10-23=0

We add all the numbers together, and all the variables

0.2x-13=0

We move all terms containing x to the left, all other terms to the right

0.2x=13

x=13/0.2

x=65

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