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.3x=1/2x-8
We move all terms to the left:
.3x-(1/2x-8)=0
Domain of the equation: 2x-8)!=0We get rid of parentheses
x∈R
.3x-1/2x+8=0
We multiply all the terms by the denominator
(.3x)*2x+8*2x-1=0
We add all the numbers together, and all the variables
(+.3x)*2x+8*2x-1=0
We multiply parentheses
2x^2+8*2x-1=0
Wy multiply elements
2x^2+16x-1=0
a = 2; b = 16; c = -1;
Δ = b2-4ac
Δ = 162-4·2·(-1)
Δ = 264
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{264}=\sqrt{4*66}=\sqrt{4}*\sqrt{66}=2\sqrt{66}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-2\sqrt{66}}{2*2}=\frac{-16-2\sqrt{66}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+2\sqrt{66}}{2*2}=\frac{-16+2\sqrt{66}}{4} $
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