.4/2m+2m=3

Solution for .4/2m+2m=3 equation:

.4/2m+2m=3

We move all terms to the left:

.4/2m+2m-(3)=0


Domain of the equation: 2m!=0

m!=0/2

m!=0

m∈R


We add all the numbers together, and all the variables

2m+.4/2m-3=0

We multiply all the terms by the denominator


2m*2m-3*2m+.4=0

We add all the numbers together, and all the variables

2m*2m-3*2m+0.4=0

Wy multiply elements

4m^2-6m+0.4=0

a = 4; b = -6; c = +0.4;
Δ = b2-4ac
Δ = -62-4·4·0.4
Δ = 29.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-\sqrt{29.6}}{2*4}=\frac{6-\sqrt{29.6}}{8}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+\sqrt{29.6}}{2*4}=\frac{6+\sqrt{29.6}}{8}
$