.40x+.20(100-x)=21

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Solution for .40x+.20(100-x)=21 equation: 



.40x+.20(100-x)=21

We move all terms to the left:

.40x+.20(100-x)-(21)=0

We add all the numbers together, and all the variables

.40x+.20(-1x+100)-21=0

We multiply parentheses

.40x-0.2x+20-21=0

We add all the numbers together, and all the variables

0.2x-1=0

We move all terms containing x to the left, all other terms to the right

0.2x=1

x=1/0.2

x=5

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