.5(10z+4)-1=4(z-2)

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Solution for .5(10z+4)-1=4(z-2) equation: 



.5(10z+4)-1=4(z-2)

We move all terms to the left:

.5(10z+4)-1-(4(z-2))=0

We multiply parentheses

5z-(4(z-2))+2-1=0



We calculate terms in parentheses: -(4(z-2)), so:

4(z-2)

We multiply parentheses

4z-8

Back to the equation:

-(4z-8)



We add all the numbers together, and all the variables

5z-(4z-8)+1=0

We get rid of parentheses

5z-4z+8+1=0

We add all the numbers together, and all the variables

z+9=0

We move all terms containing z to the left, all other terms to the right

z=-9

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