.5(2x)+.25(5y)+.25(10z)=350

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Solution for .5(2x)+.25(5y)+.25(10z)=350 equation:


Simplifying
0.5(2x) + 0.25(5y) + 0.25(10z) = 350

Remove parenthesis around (2x)
0.5 * 2x + 0.25(5y) + 0.25(10z) = 350

Multiply 0.5 * 2
1x + 0.25(5y) + 0.25(10z) = 350

Remove parenthesis around (5y)
1x + 0.25 * 5y + 0.25(10z) = 350

Multiply 0.25 * 5
1x + 1.25y + 0.25(10z) = 350

Remove parenthesis around (10z)
1x + 1.25y + 0.25 * 10z = 350

Multiply 0.25 * 10
1x + 1.25y + 2.5z = 350

Solving
1x + 1.25y + 2.5z = 350

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-1.25y' to each side of the equation.
1x + 1.25y + -1.25y + 2.5z = 350 + -1.25y

Combine like terms: 1.25y + -1.25y = 0.00
1x + 0.00 + 2.5z = 350 + -1.25y
1x + 2.5z = 350 + -1.25y

Add '-2.5z' to each side of the equation.
1x + 2.5z + -2.5z = 350 + -1.25y + -2.5z

Combine like terms: 2.5z + -2.5z = 0.0
1x + 0.0 = 350 + -1.25y + -2.5z
1x = 350 + -1.25y + -2.5z

Divide each side by '1'.
x = 350 + -1.25y + -2.5z

Simplifying
x = 350 + -1.25y + -2.5z

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