.5(4x)+(x-10)+3x=428

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Solution for .5(4x)+(x-10)+3x=428 equation: 



.5(4x)+(x-10)+3x=428

We move all terms to the left:

.5(4x)+(x-10)+3x-(428)=0

We add all the numbers together, and all the variables

3.54x+(x-10)-428=0

We get rid of parentheses

3.54x+x-10-428=0

We add all the numbers together, and all the variables

4.54x-438=0

We move all terms containing x to the left, all other terms to the right

4.54x=438

x=438/4.54

x=96+1/2.1018518518519

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