.5+(2x-1)+(2x-1)+2x=(3x-3)+(x-3)

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Solution for .5+(2x-1)+(2x-1)+2x=(3x-3)+(x-3) equation: 



.5+(2x-1)+(2x-1)+2x=(3x-3)+(x-3)

We move all terms to the left:

.5+(2x-1)+(2x-1)+2x-((3x-3)+(x-3))=0

We add all the numbers together, and all the variables

2x+(2x-1)+(2x-1)-((3x-3)+(x-3))+0.5=0

We get rid of parentheses

2x+2x+2x-((3x-3)+(x-3))-1-1+0.5=0



We calculate terms in parentheses: -((3x-3)+(x-3)), so:

(3x-3)+(x-3)

We get rid of parentheses

3x+x-3-3

We add all the numbers together, and all the variables

4x-6

Back to the equation:

-(4x-6)



We add all the numbers together, and all the variables

6x-(4x-6)-1.5=0

We get rid of parentheses

6x-4x+6-1.5=0

We add all the numbers together, and all the variables

2x+4.5=0

We move all terms containing x to the left, all other terms to the right

2x=-4.5

x=-4.5/2

x=-2+0.5/2

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