.5-(n-4)-3=3(2n+3)

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Solution for .5-(n-4)-3=3(2n+3) equation: 



.5-(n-4)-3=3(2n+3)

We move all terms to the left:

.5-(n-4)-3-(3(2n+3))=0

We add all the numbers together, and all the variables

-(n-4)-(3(2n+3))-2.5=0

We get rid of parentheses

-n-(3(2n+3))+4-2.5=0



We calculate terms in parentheses: -(3(2n+3)), so:

3(2n+3)

We multiply parentheses

6n+9

Back to the equation:

-(6n+9)



We add all the numbers together, and all the variables

-1n-(6n+9)+1.5=0

We get rid of parentheses

-1n-6n-9+1.5=0

We add all the numbers together, and all the variables

-7n-7.5=0

We move all terms containing n to the left, all other terms to the right

-7n=7.5

n=7.5/-7

n=-1+0.5/7

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