.5-(n-4)-3=3-(2n+3)

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Solution for .5-(n-4)-3=3-(2n+3) equation: 



.5-(n-4)-3=3-(2n+3)

We move all terms to the left:

.5-(n-4)-3-(3-(2n+3))=0

We add all the numbers together, and all the variables

-(n-4)-(3-(2n+3))-2.5=0

We get rid of parentheses

-n-(3-(2n+3))+4-2.5=0



We calculate terms in parentheses: -(3-(2n+3)), so:

3-(2n+3)

determiningTheFunctionDomain
-(2n+3)+3

We get rid of parentheses

-2n-3+3

We add all the numbers together, and all the variables

-2n

Back to the equation:

-(-2n)



We add all the numbers together, and all the variables

-1n-(-2n)+1.5=0

We get rid of parentheses

-1n+2n+1.5=0

We add all the numbers together, and all the variables

n+1.5=0

We move all terms containing n to the left, all other terms to the right

n=-1.5

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