.50(2c+20)=2(3c-5)

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Solution for .50(2c+20)=2(3c-5) equation:


Simplifying
0.50(2c + 20) = 2(3c + -5)

Reorder the terms:
0.50(20 + 2c) = 2(3c + -5)
(20 * 0.50 + 2c * 0.50) = 2(3c + -5)
(10 + 1c) = 2(3c + -5)

Reorder the terms:
10 + 1c = 2(-5 + 3c)
10 + 1c = (-5 * 2 + 3c * 2)
10 + 1c = (-10 + 6c)

Solving
10 + 1c = -10 + 6c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-6c' to each side of the equation.
10 + 1c + -6c = -10 + 6c + -6c

Combine like terms: 1c + -6c = -5c
10 + -5c = -10 + 6c + -6c

Combine like terms: 6c + -6c = 0
10 + -5c = -10 + 0
10 + -5c = -10

Add '-10' to each side of the equation.
10 + -10 + -5c = -10 + -10

Combine like terms: 10 + -10 = 0
0 + -5c = -10 + -10
-5c = -10 + -10

Combine like terms: -10 + -10 = -20
-5c = -20

Divide each side by '-5'.
c = 4

Simplifying
c = 4

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