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.50(n-4)-3=3-(2n+3)
We move all terms to the left:
.50(n-4)-3-(3-(2n+3))=0
We multiply parentheses
0.5n-(3-(2n+3))-2-3=0
We calculate terms in parentheses: -(3-(2n+3)), so:We add all the numbers together, and all the variables
3-(2n+3)
determiningTheFunctionDomain -(2n+3)+3
We get rid of parentheses
-2n-3+3
We add all the numbers together, and all the variables
-2n
Back to the equation:
-(-2n)
0.5n-(-2n)-5=0
We get rid of parentheses
0.5n+2n-5=0
We add all the numbers together, and all the variables
2.5n-5=0
We move all terms containing n to the left, all other terms to the right
2.5n=5
n=5/2.5
n=2
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