.6(1-x)+.2(x-5)=10

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Solution for .6(1-x)+.2(x-5)=10 equation:



.6(1-x)+.2(x-5)=10
We move all terms to the left:
.6(1-x)+.2(x-5)-(10)=0
We add all the numbers together, and all the variables
.6(-1x+1)+.2(x-5)-10=0
We multiply parentheses
-0.6x+0.2x+0.6-1-10=0
We add all the numbers together, and all the variables
-0.4x-10.4=0
We move all terms containing x to the left, all other terms to the right
-0.4x=10.4
x=10.4/-0.4
x=-26

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