.60=(100-x)(1/50)

Solution for .60=(100-x)(1/50) equation:

.60=(100-x)(1/50)

We move all terms to the left:

.60-((100-x)(1/50))=0

We add all the numbers together, and all the variables

-((-1x+100)(+1/50))+.60=0

We add all the numbers together, and all the variables

-((-1x+100)(+1/50))+0.6=0

We multiply parentheses ..

-((-1x^2+100*1/50))+0.6=0

We multiply all the terms by the denominator


-((-1x^2+100*1+(0.6)*50))=0


We calculate terms in parentheses: -((-1x^2+100*1+(0.6)*50)), so:

(-1x^2+100*1+(0.6)*50)


We calculate terms in parentheses: +(-1x^2+100*1+(0.6)*50), so:

-1x^2+100*1+(0.6)*50

We add all the numbers together, and all the variables

-1x^2+130

Back to the equation:

+(-1x^2+130)


We get rid of parentheses

-1x^2+130

Back to the equation:

-(-1x^2+130)


We get rid of parentheses

1x^2-130=0

We add all the numbers together, and all the variables

x^2-130=0

a = 1; b = 0; c = -130;
Δ = b2-4ac
Δ = 02-4·1·(-130)
Δ = 520
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{520}=\sqrt{4*130}=\sqrt{4}*\sqrt{130}=2\sqrt{130}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{130}}{2*1}=\frac{0-2\sqrt{130}}{2}
=-\frac{2\sqrt{130}}{2}
=-\sqrt{130}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{130}}{2*1}=\frac{0+2\sqrt{130}}{2}
=\frac{2\sqrt{130}}{2}
=\sqrt{130}
$