.7(2x+5)=1.1-(x+4)

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Solution for .7(2x+5)=1.1-(x+4) equation: 



.7(2x+5)=1.1-(x+4)

We move all terms to the left:

.7(2x+5)-(1.1-(x+4))=0

We multiply parentheses

1.4x-(1.1-(x+4))+3.5=0



We calculate terms in parentheses: -(1.1-(x+4)), so:

1.1-(x+4)

determiningTheFunctionDomain
-(x+4)+1.1

We get rid of parentheses

-x-4+1.1

We add all the numbers together, and all the variables

-1x-2.9

Back to the equation:

-(-1x-2.9)



We get rid of parentheses

1.4x+1x+2.9+3.5=0

We add all the numbers together, and all the variables

2.4x+6.4=0

We move all terms containing x to the left, all other terms to the right

2.4x=-6.4

x=-6.4/2.4

x=-2+1/1.5

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