.7-6(c-1)+3(3-4c)=7+(7c-4)

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Solution for .7-6(c-1)+3(3-4c)=7+(7c-4) equation: 



.7-6(c-1)+3(3-4c)=7+(7c-4)

We move all terms to the left:

.7-6(c-1)+3(3-4c)-(7+(7c-4))=0

We add all the numbers together, and all the variables

-6(c-1)+3(-4c+3)-(7+(7c-4))+.7=0

We add all the numbers together, and all the variables

-6(c-1)+3(-4c+3)-(7+(7c-4))+0.7=0

We multiply parentheses

-6c-12c-(7+(7c-4))+6+9+0.7=0



We calculate terms in parentheses: -(7+(7c-4)), so:

7+(7c-4)

determiningTheFunctionDomain
(7c-4)+7

We get rid of parentheses

7c-4+7

We add all the numbers together, and all the variables

7c+3

Back to the equation:

-(7c+3)



We add all the numbers together, and all the variables

-18c-(7c+3)+15.7=0

We get rid of parentheses

-18c-7c-3+15.7=0

We add all the numbers together, and all the variables

-25c+12.7=0

We move all terms containing c to the left, all other terms to the right

-25c=-12.7

c=-12.7/-25

c=7.47058823529/14.7058823529

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