.75(12+4a)=21+3(a-4)

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Solution for .75(12+4a)=21+3(a-4) equation: 



.75(12+4a)=21+3(a-4)

We move all terms to the left:

.75(12+4a)-(21+3(a-4))=0

We add all the numbers together, and all the variables

.75(4a+12)-(21+3(a-4))=0

We multiply parentheses

3a-(21+3(a-4))+9=0



We calculate terms in parentheses: -(21+3(a-4)), so:

21+3(a-4)

determiningTheFunctionDomain
3(a-4)+21

We multiply parentheses

3a-12+21

We add all the numbers together, and all the variables

3a+9

Back to the equation:

-(3a+9)



We get rid of parentheses

3a-3a-9+9=0

We add all the numbers together, and all the variables

=0

a=0/1

a=0

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