.99+.99(n-1)=1.29+1.29(n-1)

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Solution for .99+.99(n-1)=1.29+1.29(n-1) equation:


.99+.99(n-1)=1.29+1.29(n-1)

We simplify the equation to the form, which is simple to understand
.99+.99(n-1)=1.29+1.29(n-1)

Reorder the terms in parentheses
.99+( + 0.99n-0.99)=1.29+1.29*(n-1)

Remove unnecessary parentheses
+.99 + 0.99n-0.99=+1.29+1.29+*(+n-1+)

Reorder the terms in parentheses
.99 + 0.99n-0.99=1.29+(+1.29n-1.29)

Remove unnecessary parentheses
+.99 + 0.99n-0.99=+1.29+1.29n-1.29

We move all terms containing n to the left and all other terms to the right.
+ 0.99n-1.29n=+1.29-1.29-0.99 + 0.99

We simplify left and right side of the equation.
-0.3n=0

We divide both sides of the equation by -0.3 to get n.
n=-0

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