3(x+2)+4x-5=7(x+1)-6

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Solution for 3(x+2)+4x-5=7(x+1)-6 equation: 


Simplifying
3(x + 2) + 4x + -5 = 7(x + 1) + -6

Reorder the terms:
3(2 + x) + 4x + -5 = 7(x + 1) + -6
(2 * 3 + x * 3) + 4x + -5 = 7(x + 1) + -6
(6 + 3x) + 4x + -5 = 7(x + 1) + -6

Reorder the terms:
6 + -5 + 3x + 4x = 7(x + 1) + -6

Combine like terms: 6 + -5 = 1
1 + 3x + 4x = 7(x + 1) + -6

Combine like terms: 3x + 4x = 7x
1 + 7x = 7(x + 1) + -6

Reorder the terms:
1 + 7x = 7(1 + x) + -6
1 + 7x = (1 * 7 + x * 7) + -6
1 + 7x = (7 + 7x) + -6

Reorder the terms:
1 + 7x = 7 + -6 + 7x

Combine like terms: 7 + -6 = 1
1 + 7x = 1 + 7x

Add '-1' to each side of the equation.
1 + -1 + 7x = 1 + -1 + 7x

Combine like terms: 1 + -1 = 0
0 + 7x = 1 + -1 + 7x
7x = 1 + -1 + 7x

Combine like terms: 1 + -1 = 0
7x = 0 + 7x
7x = 7x

Add '-7x' to each side of the equation.
7x + -7x = 7x + -7x

Combine like terms: 7x + -7x = 0
0 = 7x + -7x

Combine like terms: 7x + -7x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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