7(2q+1)=35

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Solution for 7(2q+1)=35 equation: 



7(2q+1)=35

We move all terms to the left:

7(2q+1)-(35)=0

We multiply parentheses

14q+7-35=0

We add all the numbers together, and all the variables

14q-28=0

We move all terms containing q to the left, all other terms to the right

14q=28

q=28/14

q=2

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